Codechange: Add base() method to StrongType to allow access to the base type without casting. (#11445)

This removes the ability to explicitly cast to the base type, but the requirement
to use .base() means the conversion is still explicit.
This commit is contained in:
Peter Nelson
2023-11-06 20:29:35 +00:00
committed by GitHub
parent 737775f834
commit ab535c0a86
73 changed files with 174 additions and 173 deletions

View File

@@ -37,7 +37,7 @@ namespace SQConvert {
template <> struct Return<int32_t> { static inline int Set(HSQUIRRELVM vm, int32_t res) { sq_pushinteger(vm, res); return 1; } };
template <> struct Return<int64_t> { static inline int Set(HSQUIRRELVM vm, int64_t res) { sq_pushinteger(vm, res); return 1; } };
template <> struct Return<Money> { static inline int Set(HSQUIRRELVM vm, Money res) { sq_pushinteger(vm, res); return 1; } };
template <> struct Return<TileIndex> { static inline int Set(HSQUIRRELVM vm, TileIndex res) { sq_pushinteger(vm, (int32_t)static_cast<uint32_t>(res)); return 1; } };
template <> struct Return<TileIndex> { static inline int Set(HSQUIRRELVM vm, TileIndex res) { sq_pushinteger(vm, (int32_t)res.base()); return 1; } };
template <> struct Return<bool> { static inline int Set(HSQUIRRELVM vm, bool res) { sq_pushbool (vm, res); return 1; } };
template <> struct Return<char *> { /* Do not use char *, use std::optional<std::string> instead. */ };
template <> struct Return<const char *> { /* Do not use const char *, use std::optional<std::string> instead. */ };