--Guess attack speed by taking entire data set and comparing 2 - 4 intervals then storing the n into seperate array and incrementing it
--Attack speed with most counts in latter array is the best guess by m%
--Correct this by repeating step on exit combat maybe?
--Look at tolerances as well

local dataSet2s = {
	[1] = 540390408.9506,
	[2] = 540392394.9163,
	[3] = 540394398.5326,
	[4] = 540396409.5288,
	[5] = 540398396.6414,
	[6] = 540400397.0754,
	[7] = 540402384.8113,
	[8] = 540404385.3304,
	[9] = 540406398.99,
	[10] = 540408386.472,
	[11] = 540410386.9851,
	[12] = 540412374.8497,
	[13] = 540414375.1427,
	[14] = 540416373.0995,
	[15] = 540418376.9931,
	[16] = 540420390.6971,
}
local dataSet1p5s = {
	[1] = 541651364.1916,
	[2] = 541652857.9058,
	[3] = 541654365.8491,
	[4] = 541655858.3292,
	[5] = 541657352.4962,
	[6] = 541658846.2963,
	[7] = 541660354.015,
	[8] = 541661847.0112,
	[9] = 541663340.6759,
	[10] = 541664861.3772,
	[11] = 541666354.9449,
	[12] = 541667848.8308,
	[13] = 541669343.2332,
	[14] = 541670849.9777,
	[15] = 541672344.0613,
	[16] = 541673851.2346,
}
local tolerance = 50
local tempAverages = {}
-- rounds .5 to 0 or 1; want to round to .5 or .2 or alike
for k, v in ipairs(dataSet1p5s) do
	if k > 1 then
		local tempAvg = (dataSet1p5s[k] - dataSet1p5s[k - 1])
		print(
			((math.floor(tempAvg / 1000) - (tempAvg / 1000)) * 1000),
			(math.ceil(tempAvg / 1000) - (tempAvg / 1000)) * 1000
		)
		if not tempAverages[tempAvg] then tempAverages[tempAvg] = 0 end
		tempAverages[tempAvg] = tempAverages[tempAvg] + 1
	end
end
for k, v in pairs(tempAverages) do
	print(k, v)
end